Question

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A spy realizes his cover is blown and flees toward his secret evacuation spot at a speed of 60 mph. Two hours later, a special agent in a helicopter starts chasing the spy. The special agent travels the same route at a speed of 90 mph.


A What distance does the spy cover in t hours?
B What distance does the special agent cover in t hours?
C How fast is the distance between them reducing
D How far apart are the spy and special agent when the chase begins?
E How long does it take the special agent to catch the spy?
F At what speed should the special agent chase the spy if the evacuation spot is 240 miles from the setting point

Answer 1

The spy will cover a distance of 60t in t hours and the special agent will cover a distance of 90t in t hours.

What is distance?

Distance is actually known as the amount of space between two points. When calculating speed, it is given as:

Speed = distance ÷ time

The spy's distance in t hours:

Distance = 60 × t = 60t.

The special agent's distance in t hours:

Distance = 90 × t = 90t

The distance between them will be =

Distance of special agent minus distance of the spy: 90t - 60t = 30t.

By the time the chase begins, the distance between the spy and special agent will be:

(2 × 60mph) - 0 = 120m - 0.

= 120m.

Time taken for the special agent to catch the spy: 120 + 60t = 90t

120 = 90t - 60t

120 = 30t

t = 120/30 = 4 hours.

Speed the special agent should chase the spy:

Distance = 240 miles

Time = 4 hours.

Then Speed = 240/4 = 60mph.

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