Question

A 1. 5-kω resistor and 27. 7-mh inductor are connected in series to a vrms = 120 v ac power source oscillating at a frequency of f = 60 hz. The voltage as a function of time is given by

Answer 1

The voltage as a function of time for the power source oscillating at the given frequency is determined as V = 169.7sin(120πt).

Peak voltage

The peak voltage of the source is calculated as follows;

Vrms = 0.7071V₀

120 = 0.7071V₀

V₀ = 120/0.7071

V₀ = 169.7 V

Angular frequency of the wave

ω = 2πf

where;

f is frequency = 60 Hz

ω = 2π x 60

ω = 120π rad/s

Voltage equation as function of time

V = V₀sin(ωt)

V = 169.7sin(120πt)

Learn more about peak voltage here: https://brainly.com/question/6249123

Answer 2

The voltage equation is a function of a time is V = 169.7sin(120πt) if the 1. 5-kω resistor and 27. 7-mh inductors are connected in series to a vrms = 120 v ac power source oscillating at a frequency of f = 60 Hz.

What is induced voltage?

Electromagnetic induction causes the induced voltage. Electromagnetic induction is the process of creating emf (induced voltage) by exposing a conductor to a magnetic field.

We have:

$\rm V{rms} = 120$

We know:

$\rm V_{rms} = 0.7071V_o$

$\rm 120 = 0.7071V_o$

$\rm V_o = 169.70$ Volts

Expression for the angular frequency is given by:

ω = 2πf

Where f is frequency

ω = 2π x 60  

ω = 120π rad/s

Voltage equation as a function of time is given by:

V = V₀sin(ωt)

V = 169.7sin(120πt)

Thus, the voltage equation is a function of a time is V = 169.7sin(120πt) if the 1. 5-kω resistor and 27. 7-mh inductors are connected in series to a vrms = 120 v ac power source oscillating at a frequency of f = 60 Hz.

Learn more about the induced voltage here:

brainly.com/question/19482771

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