Question

What is the length of the hypotenuse of the triangle?


Triangle A B C. Side A C is 7 feet and side C B is 4 feet. Hypotenuse A B is unknown.
StartRoot 22 EndRoot ft
StartRoot 33 EndRoot ft
StartRoot 57 EndRoot ft
StartRoot 65 EndRoot ft

Answer 1

Answer:

The last answer $\sqrt{65}$

Step-by-step explanation:

$7^2+4^2 = 65$

The formula to find it is $a^2+b^2=c^2$

so $\sqrt{65}$ is correct

Answer 2

Answer:

• √65 ft (Option D)

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Step-by-step explanation:

• This is Right Angled Triangle.

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We'll solve this using the Pythagorean Theorem.

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• AC = 7ft which is the Base.

• BC = 4 ft which is the Perpendicular.

• AB is the Hypotenuse.

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We know that,

${ \longrightarrow \pmb{\qquad \: (AB) {}^{2} = (AC) {}^{2} + ( BC) {}^{2}}}$

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${ \longrightarrow \sf{\qquad \: (AB) {}^{2} = (7) {}^{2} + ( 4) {}^{2}}}$

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${ \longrightarrow \sf{\qquad \: (AB) {}^{2} = 49 + 16}}$

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${ \longrightarrow \sf{\qquad \: (AB) {}^{2} = 65}}$

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${ \longrightarrow \sf {\pmb {\qquad \: AB}}} = \pmb{ \frak{\sqrt{65}}}$

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Therefore,

• The length of the Hypotenuse (AB) is √65 ft