Question

in the lab, Kareem has two solutions that contain alcohol and is mixing them with each other. Solution A is 2% alcohol and Solution B is 7% alcohol. He uses 1200 milliliters of Solution A. How many milliliters of Solution B does he use, if the resulting mixture is a 4% alcohol solution?

Answer 1

Answer:

800ml

Step-by-step explanation:

solution A= 2% alcohol

solution B=7% alcohol

1200ml=1.2L

1200ml=1200cm^3

X= solution B

solution A + solution B=(1200+x)cm^3

% alcohol= amount of alcohol/total solution(AorB)×100

☆in 1200ml of solution A there's

0.02x1200

2x12

=24ml of alcohol (in 1200ml of solution A)

0.07x X

=0.07Xml of alcohol (in some ml of solution B)

(24+0.07X)ml of alcohol in = solution A and solution B

solution A + solution B= 1200+X

0.04 (1200+X)=24+0.07X

48+0.04X=24+0.07X

48-24=0.07X-0.04X

24=0.03X

X=800ml