Question

Given that 1 x2 dx 0 = 1 3 , use this fact and the properties of integrals to evaluate 1 (4 − 6x2) dx. 0

Answer 1

So, the definite integral  $\int\limits^1_0 {(4 - 6x^{2} )} \, dx= - 74$

Given that

$\int\limits^1_0 {x^{2} } \, dx = 13$

We find

$\int\limits^1_0 {(4 - 6x^{2} )} \, dx$

Definite integrals

Definite integrals are integral values that are obtained by integrating a function between two values.

So, $Integral \int\limits^1_0 {(4 - 6x^{2} )} \, dx$

So, $\int\limits^1_0 {(4 - 6x^{2} )} \, dx = \int\limits^1_0 {4} \, dx - \int\limits^1_0 {6x^{2} } \, dx \\= 4[x]^{1}_{0} - \int\limits^1_0 {6x^{2} } \, dx \\= 4[x]^{1}_{0} - 6\int\limits^1_0 {x^{2} } \, dx \\= 4[1 - 0] - 6\int\limits^1_0 {x^{2} } \, dx\\= 4[1] - 6\int\limits^1_0 {x^{2} } \, dx\\= 4 - 6\int\limits^1_0 {x^{2} } \, dx$

Since

$\int\limits^1_0 {x^{2} } \, dx = 13$,

Substituting this into the equation the equation, we have

$\int\limits^1_0 {(4 - 6x^{2} )} \, dx = 4 - 6\int\limits^1_0 {x^{2} } \, dx\\= 4 - 6 X 13 \\= 4 - 78\\= -74$

So, $\int\limits^1_0 {(4 - 6x^{2} )} \, dx= - 74$

Learn more about definite integrals here:

https://brainly.com/question/17074932

Answer 2

The value of the function $\rm \int\limits{(4-6x^2)} \, dx$ is -74.

What is a definite integral?

A definite Integral is a difference between the values of the integral at the specified upper and lower limit of the independent variable.

The given function is;

$\rm \int\limits^1_0 {x^2} \, dx=13$

Calculation of the value of the function by using integration;

$\rm= \int\limits{(4-6x^2)} \, dx \\\\=4 \int\limits^1_0 {} \, dx -6\int\limits^1_0 {x^2} \, dx \\\\=4 \int\limits^1_0 {} \, dx -6(13)\\\\ =4[x]^1_0-78\\\\= 4[1-0]-78\\\\=4-78\\\\=-74$

Hence, the value of the function $\rm \int\limits{(4-6x^2)} \, dx$ is -74.

To know more about definite integration click the link given below.

https://brainly.com/question/18125359

#SPJ4