Question

image Consider the graph of g(x) = x2 – 8x + 12. Identify the y-intercept, the vertex, and the zeros of the function.

Answer 1

Answer:

Below in bold.

Step-by-step explanation:

g(x) = x^2 – 8x + 12

Convert to vertex form:

g(x) = (x - 4)^2 - 16 + 12

g(x) = (x - 4)^2 - 4.

So the vertex is at (4, -4).

y-intercept (when x = 0) is ((0-4)^2 - 4 = 16 - 4

- that is (0, 12).

Zeros:

(x - 4)^2 - 4 = 0

(x - 4)^2 = 4

x - 4 = +/- 2

x = 2 + 4 = 6 or x = -2 + 4 = 2.

= 2, 6.