The percentage of area under a normal curve between the mean and the standard deviations is 81.59%
Z score is used to determine by how many standard deviations the raw score is above or below the mean. It is given by:
z = (raw score - mean) / standard deviation
Hence:
P(z < 0.9) = 0.8159
The percentage of area under a normal curve between the mean and the standard deviations is 81.59%
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