Question

PLEASE HELP ME!!!!!!!!!

Answer 1

Answer:

$\displaystyle 13 = b_1$

Step-by-step explanation:

$\displaystyle h[b_2 + b_1] \div 2 = A \\ \\ 99 = 6[20 + b_1] \div 2 \hookrightarrow \frac{198}{6} = \frac{6[20 + b_1]}{6}; 33 = 20 + b_1 \\ \\ \boxed{13 = b_1}$

OR

$\displaystyle \frac{1}{2}h[b_2 + b_1] = A \\ \\ 99 = \frac{1}{2}[6][20 + b_1] \hookrightarrow \frac{99}{3} = \frac{3[20 + b_1]}{3}; 33 = 20 + b_1 \\ \\ \boxed{13 = b_1}$

I am joyous to assist you at any time.