Question

Starting with the following equation,
BaCl2(aq) + Na3PO4(aq) → Ba3(PO4)2(S) + NaCl(aq)

Calculate the mass in grams of BaCl2 that will be required to produce 50.5 grams of Ba3(PO4)2.

Answer 1

In the double displacement reaction between BaCl₂ and Na₃PO₄, 52.4 g of BaCl₂ are required to produce 50.5 g of Ba₃(PO₄)₂.

What is stoichiometry?

Stoichiometry refers to the relationship between the quantities of reactants and products before, during, and following chemical reactions.

• Step 1: Write the unbalanced equation.

BaCl₂(aq) + Na₃PO₄(aq) → Ba₃(PO₄)₂(s) + NaCl(aq)

• Step 2: Balance the equation.

We will use the trial and error method. We will:

• Multiply BaCl₂ by 3 to balance Ba atoms.
• Multiply Na₃PO₄ by 2 to balance P atoms.
• Multiply NaCl by 6 to get the balanced equation.

3 BaCl₂(aq) + 2 Na₃PO₄(aq) → Ba₃(PO₄)₂(s) + 6 NaCl(aq)

• Step 3: Calculate the mass of BaCl₂ required to produce 50.5 g of Ba₃(PO₄)₂.

The mass ratio of BaCl₂ to Ba₃(PO₄)₂ is 624.69:601.93.

50.5 g Ba₃(PO₄)₂ × 624.69 g BaCl₂/601.93 g Ba₃(PO₄)₂ = 52.4 g BaCl₂

In the double displacement reaction between BaCl₂ and Na₃PO₄, 52.4 g of BaCl₂ are required to produce 50.5 g of Ba₃(PO₄)₂.

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