Answer:
1. [tex]C.\ y^8-\frac{1}{y^8}[/tex]
2. [tex]E.\ \frac{1}{y^8}+\frac{1}{y^2}[/tex]
Step-by-step explanation:
1.
[tex]y^5y^3-(y^{-2})^4\\\\y^{5+3}-(y^{-2*4})\\\\y^8-(y^{-8})\\\\y^8-y^{-8}\\\\y^8-\frac{1}{y^8}[/tex]
2.
[tex](y^{-2})^4+\frac{y^3}{y^5} \\\\y^{-8}+\frac{1}{y^{5-3}}\\\\y^{-8}+\frac{1}{y^2}\\\\\frac{1}{y^8}+\frac{1}{y^2}[/tex]
Hope this helps!
