Question

Please Help i need help asap Please

Answer 1

Given -

A sequence 7, 14, 21,...

To find -

the sixteenth term of the sequence.ie., a60.

Concept -

The number a is the first term, and d is the common difference of the sequence. The nth term of an arithmetic sequence is given by

$\sf{a_n = a + (n - 1)d}$

Solution -

A.T.Q,

a = 7

n = 60

d = 14 - 7 = 7

Putting the values,

$\rightarrow\sf{a_{60} = 7 + (60- 1)7}$

$\rightarrow\sf{a_{60} = 7 + 59\times7}$

$\rightarrow\sf{a_{60} = 7 + 413}$

$\rightarrow\boxed{\green{\bf{a_{60} = 420}}}$

Answer 2

Answer:

• 60th term of sequence is 420

Step-by-step explanation:

In this question we have given a sequence or you can say it arithmetic progression which is 7 , 14 , 21,.. and we have asked to find it's 60th term .

From sequence 7 , 14 , 21.... :

• a = first term = 7

• d = common difference = 14 - 7 = 7

As we know that :

$\rightarrow \: \blue{ \boxed{a_n = a + (n - 1)d}} \leftarrow$

Where ,

• a refers to first term

• n refers to number of term

• d refers to common difference

Now , substituting values :

$\longmapsto \: a_{60} = 7 + (60 - 1)7$

Now , calculating :

$\longmapsto \: a_{60} =7 + (59)7$

$\longmapsto \: a_{60} =7 + 413$

$\longmapsto \: \pink{ \boxed{ a_{60} =420}}$

• Therefore , value of 60th term of the given sequence is 420 .

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