Answer:
Input x = -5 into f(x) = 0.5x - 3
⇒ f(-5) = 0.5(-5) - 3 = -5.5
Therefore, plot an open circle at (-5, -5.5)
Calculate another point, draw a line from (-5, -5.5) through the other point. As the function has the domain x < -5 it has one endpoint at (-5, -5.5). Therefore, add an arrow to the other end to show that it is continuous.
Input x = -5 and x = 3 in f(x) = x + 2
⇒ f(-5) = -5 + 2 = -3
⇒ f(3) = 3 + 2 = 5
Plot closed circles at (-5, -3) and (3, 5). Join the points with a line segment.
Input x = 3 into f(x) = -2x
⇒ f(3) = -2(3) = -6
Therefore, plot an open circle at (3, -6)
Calculate another point, draw a line from (3, -6) through the other point. As the function has the domain x > 3 it has one endpoint at (3, -6). Therefore, add an arrow to the other end to show that it is continuous.
