Answer:
[tex]6 \: or \: \frac{1}{3} [/tex]
Step-by-step explanation:
[tex]3b {}^{2} - 19b + 1 = - 5 \\ 3b {}^{2} - 19b + 1 + 5 = 0 \\ 3b {}^{2} - 19b + 6 = 0 \\ 3b {}^{2} - b - 18b + 6 = 0 \\ b(3b - 1) - 6(3b - 1) = 0\\ (b - 6)(3b - 1) = 0 \\ b = 6 \: or \: 3b = 1 \\ b = 6 \: orb = \frac{1}{3} [/tex]