Question

What is an equation of the line that passes through (0, 4) and (2,8)?

Answer 1

Answer:

y=2x+4

Step-by-step explanation:

Hi there!

We are given the points (0, 4) and (2,8)

We want to write the equation of the line that passes through these two points

There are 3 ways to write the equation of the line, but the most common way is with slope-intercept form, which is y=mx+b, where m is the slope and b is the y intercept

So, to use this way, we need to find the slope of the line

The slope can be calculated using the formula $\frac{y_2-y_1}{x_2-x_1}$, where $(x_1, y_1)$ and $(x_2, y_2)$ are points

We are already given the points needed to find the slope, but let's label them to avoid any confusion

$x_1=0\\y_1=4\\x_2=2\\y_2=8$

Now substitute these values into the formula.

m=$\frac{y_2-y_1}{x_2-x_1}$

m=$\frac{8-4}{2-0}$

Subtract

m=$\frac{4}{2}$

Divide

m=2

The slope of the line is 2

Here is the equation of the line so far:

y=2x+b

Now we need to find b

As stated before, b is the y intercept of the line, which is the point in where the line passes through the y axis; the value of x at this point is 0

One of the points we were given earlier is actually the y intercept of the line; that point is (0, 4) *notice how x=0 at this point

The value of b is the value of y at the y intercept; in this case, the value of b is 4

Substitute 4 as b into the equation

y=2x+4

Hope this helps!

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