christianpalmer6373 christianpalmer6373
  • 31-03-2022
  • Mathematics
contestada

Write the equation of the circle centered at (3, 5) and tangent to x = -1. I need help pleasse

Respuesta :

jimrgrant1 jimrgrant1
  • 31-03-2022

Answer:

(x - 3)² + (y - 5)² = 16

Step-by-step explanation:

the equation of a circle in standard form is

(x - h)² + (y - k)² = r²

where (h, k ) are the coordinates of the centre and r the radius

given (h, k ) = (3, 5 ) we require to find r

r is the distance from the centre to a point on the circle

given x = - 1 is a tangent the r is the distance between the x- coordinates

r = | 3 - (- 1) | = | 3 + 1 | = | 4 | = 4

then equation of circle is

(x - 3)² + (y - 5)² = 4² , that is

(x - 3)² + (y - 5)² = 16

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