Question

Consider the reaction.

A(aq)↽−−⇀2B(aq)=4.87×10−6 at 500 K

If a 2.00 M sample of A is heated to 500 K, what is the concentration of B at equilibrium?

Answer 1

Note the signs of equilibrium:-

• Reaction don't procede forward or backward
• Concentration of products and reactants remains same .

So

if

Concentration of A is 2M then concentration of B should be same .

So equilibrium constant K is 1

$\\ \rm\rightarrowtail K=\dfrac{[Products]^a}{[Reactants]^b}$

So

• [B]=[A]^2
• [B]=2^2
• [B]=4M