Question

:-QUESTION:-

*AD is a diameter of a circle and AB is a chord if AD = 34 cm, AB = 30 cm then find the distance of AB from the centre of chord.*​
........._______|
​

Answer 1

$\sf AB \longrightarrow \sqrt{ {34}^{2} - {30}^{2} }$

$\sf AB \longrightarrow \sqrt{(34 \times 34) - (30 \times 30)}$

$\sf AB \longrightarrow \sqrt{1.156 - 900}$

$\sf AB \longrightarrow \sqrt{256}$

$\sf AB \longrightarrow \sqrt{ {16}^{2} }$

$\sf AB \longrightarrow 16 ~cm$