Question

16=2(-8t-1)(t-2) solve for t​

Answer 1

hi there! so here's my answer

$\rm \tiny\color{green}t = \frac{10}{9} \\ \\ \tt \: in \: alternative \: form \\ \\ \color{yellow} \rm \: t = 1 \frac{1}{9} \: \: \: or \: \: t = 1.1$

Step-by-step explanation:

$\color{gray} \tt \: 16 = 2( - 8t - 1) \times (t - 2)$

• calculate the difference

$\color{gray} \tt \: 16 = 2(- 9)(t - 2)$

• multiplying an odd number of negative terms makes the product negative

$\color{gray} \tt \: 16=^ \ 2*9(t-2)$

• multiply the numbers

$\color{gray} \tt \: 16=-18 (t-2)$

• distribute - 18 trough the parentheses

$\color{gray} \tt \: 16 = - 18t + 36$

• move the variable to the left hand side and change its sign

$\color{gray} \tt \:16+18t=36$

• move the constant to the right-hand side and change its sign

$\color{gray} \tt \:18t=36-16$

• substract

$\color{gray} \tt \:18t=20$

• by both sides of the equation by 18

$\:\rm \tiny\color{green}t = \frac{10}{9} \\ \\ \tt \: in \: alternative \: form \\ \\ \color{yellow} \rm \: t = 1 \frac{1}{9} \: \: \: or \: \: t = 1.1$

hope it helps