Question

A ball is thrown into the air so that its height, h, in meters after t seconds is h = - 6t'2 + 15t + 3.5. When will the ball hit the ground? 2​

Answer 1

Answer:

h = -16t^ 2 + 20t + 6     ....the ball will hit the ground when h  = 0 0 = -16t^2  + 20t   + 6      factor 0  = ( -8t  -  2 )  ( 2t  - 3)     set each  factor to 0 -8t  -  2  =  0                                 and                  2t  - 3   = 0 -8t   = 2                                                                 2t   =   3 t  = -2/8  = - 1/4  sec   [reject]                                t  = 3/2 sec  = 1.5 sec  Max ht  will be reached at [ -b / 2a ]    sec    =  -20 / [ 2(-16)]  =  20/32  =  5/8 sec Sub this back ino the function -16(5/8)^ 2 + 20(5/8) + 6  =   12.25  ft

Step-by-step explanation:

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