Answer:
x = -11/2 , y = -1/6
Step-by-step explanation:
Given:
[tex]\begin{bmatrix}-x-3y=6\\ 2x+3=-8\end{bmatrix}[/tex]
Solve:
[tex]\mathrm{Substitute\:}x=-\frac{11}{2}[/tex]
[tex]\begin{bmatrix}-\left(-\frac{11}{2}\right)-3y=6\end{bmatrix}[/tex]
[tex]Simplify[/tex]
[tex]\begin{bmatrix}\frac{11}{2}-3y=6\end{bmatrix}[/tex]
[tex]\mathrm{The\:solutions\:to\:the\:system\:of\:equations\:are:}[/tex]
[tex]x=-\frac{11}{2},\:y=-\frac{1}{6}[/tex]
Hence, x = -11/2 , y = 1/6
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