How many compounds are in 4.00moles of calcium bicarbonate?

There are 2.41 × 10²⁴ compounds in 4.00moles of calcium bicarbonate (CaCO3).
The number of compounds of a substance can be calculated by multiplying the number of moles of the substance by Avogadro's number. That is;
no. of compounds = no. of moles × 6.02 × 10²³
According to this question, there are 4.00moles of calcium bicarbonate. The number of compounds in CaCO3 is calculated as follows:
no. of compounds = 4 × 6.02 × 10²³
no. of compounds = 24.1 × 10²³
Therefore, there are 2.41 × 10²⁴ compounds in 4.00moles of calcium bicarbonate (CaCO3).
Learn more about compounds at: https://brainly.com/question/1445383