Question

A sample of aluminum chloride (AIC1z) has a mass of 37.2 g.
a. How many aluminum ions are present?
b. How many chloride ions are present?
c. What is the mass in grams of one formula unit of aluminum chloride?

Answer 1

The answers to your questions are as follows

A) The number of aluminium ions present = 1.62 * 10²³ ions

B) The number of chloride ions present = 9.86 * 10²³  ions

C) The mass of one unit of aluminium chloride = 133.34 grams

Given data :

mass of aluminium chloride = 37.2 g

molar mass of aluminium chloride = 133.34 g/mol

note : I mole of a molecule has 6 * 10²³ molecules  

Number of moles = mass / molar mass = 0.27 moles

Determine the number of aluminum ions and chloride ions present

A) aluminium ions present

moles of AlCl₃ * 6 * 10²³

= 0.27 * 6 * 10²³   = 1.62 * 10²³ ions

B) Chloride ions present

moles of AlCl₃ * 6 * 10²³  * 3

= 0.27 * 6 * 10²³ * 3

= 4.86 * 10²³ ions

C) The mass of one formula unit of aluminium chloride = 133.34 grams

Hence we can conclude that the answers to your question are as listed above.

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