Question

Consider the combustion reaction for acetylene. 2c2h2(l) 5o2(g) right arrow. 4co2(g) 2h2o(g) if the acetylene tank contains 37.0 mol of c2h2 and the oxygen tank contains 81.0 mol of o2, what is the limiting reactant for this reaction? c2h2 o2 co2 h2o

Answer 1

The limiting reactant for the combustion reaction for acetylene is oxygen.

What is limiting reagent?

Limiting reagents are those reagent which is present in less quantity as compared to the other reagent present for the formation of product.

Given chemical reaction is:

2C₂H₂(l) + 5O₂(g) → 4CO₂(g) + 2H₂O(g)

From the stoichiometry of the reaction, it is clear that:

2 moles of C₂H₂ = react with 5 moles of O₂

37 moles of C₂H₂ = react with 5/2×37=92.5 moles of O₂

And given moles of oxygen is 81 moles.

81 moles of O₂ = reacts with 2/5×81=32.4 moles of C₂H₂

And given moles of C₂H₂ = 81 moles.

Hence, O₂ is the limiting reagent.

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Answer 2

Answer:

O2 is the limiting reactant.