Question

How many moles of Oxygen gas are in a container that has a total volume of 33.0L at a pressure of 96.2kPa and a temperature of 35°C.

ideal gas constant= 8.31$\frac{L(kPa)}{mol(K)}$

Answer 1

A 33.0-L container at 96.2 kPa and 35 °C contains 1.24 moles of oxygen.

What is an ideal gas?

An ideal gas is a hypothetical gas whose molecules occupy negligible space and have no interactions, and which consequently obeys the gas laws exactly.

First, we will convert 35°C to Kelvin using the following expression.

K = °C + 273.15 = 35 + 273.15 = 308 K

We want to calculate the number of moles of oxygen in a 33.0-L container at 96.2 kPa and 308 K. We will use the ideal gas equation.

P × V = n × R × T

n = P × V / R × T

n = 96.2 kPa × 33.0 L / (8.31 l.kPa/mol.K) × 308 K = 1.24 mol

where,

• P is the pressure.
• V is the volume.
• n is the number of moles.
• R is the ideal gas constant.
• T is the absolute temperature.

A 33.0-L container at 96.2 kPa and 35 °C contains 1.24 moles of oxygen.

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