Question

someone help me please

Answer 1

Answer:

3x + 5y = 15

Find gradient:

coordinates taken: (5, 0), (0, 3)

$\rightarrow \sf \dfrac{y_2-y_1}{x_2-x_1}$

$\rightarrow \sf \dfrac{3-0}{0-5}$

$\rightarrow \sf -\dfrac{3}{5}$

• Here the y-intercept: 3

• gradient: -3/5

equation:

$\sf \bold{ y = m(x) + b}$

$\rightarrow \sf y = -\dfrac{3}{5} x + 3$

$\rightarrow \sf y = -\dfrac{3}{5} x + \dfrac{15}{5}$

$\rightarrow \sf 5y =-3x+15$

$\rightarrow \sf 3x+5y =15$

Answer 2

Take two points

• (0,3)
• (5,0)
• x intercept=a=5
• y intercept=b=3

So

equation of line in intercept form

$\\ \rm\rightarrowtail \dfrac{x}{a}+\dfrac{y}{b}=1$

$\\ \rm\rightarrowtail \dfrac{x}{5}+\dfrac{y}{3}=1$

• Multiply each by 15

$\\ \rm\rightarrowtail 3x+5y=15$