I need help with this question

Answer:
Length: 20, Width=34
Step-by-step explanation:
Say the length of the width is w, and the length of the length is l. Then, we can establish an equation of W=2L-6. Since the area of a rectangle is W*L, we can substitute W with 2L-6. If we multiply 2L-6 and L, we get [tex]2L^{2} -6L[/tex]=680. We can simplify this equation by dividing everything by 2. We then get [tex]L^{2}-3L=340[/tex]. If we solve for L, we get 20. Now, we plug 20 into the equation, W=2L-6. Since W=2(20)-6, which simplifies to W=40-6 which is 34, we get a width of 34.
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