Answer:
[tex]\huge\boxed{\sf P =624.678 \ kPa}[/tex]
Explanation:
Given:
Volume = v = 4.34 L
Temp = T = 1.0 °C = 1 + 273 = 274 K
Moles = n = 1.19 mol
Gas constant = R = 0.08206 L atm K⁻¹ mol ⁻¹
Required:
Pressure = P = ?
Formula:
Pv = nRT
Solution:
Rearranging formula
[tex]\displaystyle P = \frac{nRT}{v} \\\\P = \frac{(1.19)(0.08206)(274)}{4.34} \\\\P = \frac{26.8}{4.34} \\\\P = 6.17 atm\\\\\underline{In \ kPa:}\\\\P =624.678 \ kPa\\\\\rule[225]{225}{2}[/tex]
