Which of the following are solutions to the equation below? Check all that apply 4x^2 + 20x + 25 = 49

Answer:
Simplify and Quadratic Formula [tex]4x^2+20x+25-49=0\\4x^2+20x-24=0\\x_{1,\:2}=\frac{-20\pm \sqrt{20^2-4\cdot \:4\left(-24\right)}}{2\cdot \:4}\\\\x_{1,\:2}=\frac{-20\pm \:28}{2\cdot \:4}\\\\x_1=\frac{-20+28}{2\cdot \:4},\:x_2=\frac{-20-28}{2\cdot \:4}\\\\x=1,\:x=-6[/tex]
Step-by-step explanation: