Answer:
[tex]\huge\boxed{\sf v = 62.7 \ L}[/tex]
Explanation:
Given Data:
Mole = n = 3.38 mol
Temp = t = 269 K
Pressure = 1.19 atm
Gas constant = R = 0.08206 L atm K⁻¹ mol⁻¹
Required:
Volume = v = ?
Formula:
Pv = nRT
Solution:
Rearranging formula
[tex]\displaystyle v = \frac{nRT}{P} \\\\v = \frac{(3.38)(0.08206)(269)}{1.19} \\\\v = \frac{74.6}{1.19} \\\\v = 62.7 \ L\\\\\rule[225]{225}{2}[/tex]
