Answer:
centre (5, 6 ) , r = [tex]\sqrt{37}[/tex]
Step-by-step explanation:
the equation of a circle in standard form is
(x - h)² + (y - k)² = r²
where (h, k ) are the coordinates of the centre and r the radius
given
x² + y² - 10x - 12y + 24 = 0 ( collect x and y terms together and subtract 24 from both sides )
x² - 10x + y² - 12y = - 24
using the method of completing the square
add ( half the coefficient of the x / y terms)² to both sides
x² + 2(- 5)x + 25 + y² + 2(- 6)y + 36 = - 24 + 25 + 36
(x - 5)² + (y - 6)² = 37 ← in standard form
with centre (h, k ) = (5, 6 ) and r = [tex]\sqrt{37}[/tex]
