Question

What is the area of a square with vertices: G(1, 0), O(5, 2), A(3, 6) and T(-1, 4)? Show your work!

Answer 1

By finding the side length of the square, we will see that the area is 20 square units.

How to get the area of a square?

For a square of side length S, the area is:

A = S^2

In this case, the side length of the square will be the distance between two consecutive vertices, so we can say that S is the distance between points G and O.

Remember that the distance between two points (x₁, y₁) and (x₂. y₂) is:

$d = \sqrt{(x_2 - x_1)^2 + (y_2 - y_1)^2}$

So the distance between the points G(1, 0) and O(5, 2) is:

$S = \sqrt{(5 - 1)^2 + (2 - 0)^2} = \sqrt{20}$

Then the area of this square is:

$A = S^2 = (\sqrt{20})^2 = 20$

The area is 20 square units.

If you want to learn more about squares, you can read:

https://brainly.com/question/24487155