Really need help, I’m trying to catch up in my math and get my marks back up before mid term..

Answer:
a) 12x + 22 b) 17[tex]x^{2}[/tex] - x
Step-by-step explanation:
Perimeter is the sum of the each side length.
The first example is a rectangle so the (4x+8) and the (2x+3) are doubled.
(4x+8) x 2 = 8x+16
(2x+3) x 2 = 4x + 6
12x+22
(6[tex]x^{2}[/tex] - 12x) + (2[tex]x^{2}[/tex] + x) + (9[tex]x^{2}[/tex] + 10x)
combine like-terms.
17[tex]x^{2}[/tex] - x
Answer:
12x + 22 for the rectangle, 17x^2 - x for the triangle
Step-by-step explanation:
The perimeter of a square/rectangle is equal to 2*width + 2*length
So for the rectangle, it would be 2*(4x + 8) + 2*(2x + 3)
This can be further simplified as 8x + 16 + 4x + 6
Which can be further simplified as 12x + 22
The perimeter of a triangle is equal to length if side one + length of side two + length of base
That would be (6x^2 - 12x) + (2x^2 + x) + (9x^2 + 10x)
Which becomes 8x^2 - 11x + (9x^2 + 10x)
17x^2 - x