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Really need help, I’m trying to catch up in my math and get my marks back up before mid term..

Really need help Im trying to catch up in my math and get my marks back up before mid term class=

Respuesta :

Answer:

a) 12x + 22   b) 17[tex]x^{2}[/tex] - x

Step-by-step explanation:

Perimeter is the sum of the each side length.

The first example is a rectangle so the (4x+8) and the (2x+3) are doubled.

(4x+8) x 2 = 8x+16

(2x+3) x 2 = 4x + 6

12x+22

(6[tex]x^{2}[/tex] - 12x) + (2[tex]x^{2}[/tex] + x) + (9[tex]x^{2}[/tex] + 10x)

combine like-terms.

17[tex]x^{2}[/tex] - x

Answer:

12x + 22 for the rectangle, 17x^2 - x for the triangle

Step-by-step explanation:

The perimeter of a square/rectangle is equal to 2*width + 2*length

So for the rectangle, it would be 2*(4x + 8) + 2*(2x + 3)

This can be further simplified as 8x + 16 + 4x + 6

Which can be further simplified as 12x + 22

The perimeter of a triangle is equal to length if side one + length of side two + length of base

That would be (6x^2 - 12x) + (2x^2 + x) + (9x^2 + 10x)

Which becomes 8x^2 - 11x + (9x^2 + 10x)

17x^2 - x

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