Question

The area of a rectangular field is 1.12×10^45 square feet. If the length of the field is 7×10^11 feet, and the width of the field can be written as 1.6×10x feet, what is the value of x?

Answer 1

Answer:

x = 10^34

Step-by-step explanation:

length × width = area

area/length = width

width = (1.12 × 10^45 ft²)/(7 × 10^11 ft)

width = 1.12/7 × (10^45)/(10^11)   ft

width = 0.16 × 10^34  ft

width = 1.6 × 10^34  ft

width = 1.6 × x  ft

x = 10^34

Answer 2

The value of x is $10^3^2$  or $\rm x =10^3^2$

It is given that the area of a rectangular field is  $\rm 1.12\times10^4^5 \ feet^2$

It is required to find the value of x

What is the area of the rectangle?

It is defined as the space occupied by the rectangle which is planner 2-dimensional geometry.

The formula for finding the area of a rectangle is given by:

Area of rectangle = length × width

We have:

Area of rectangle = $\rm 1.12\times10^4^5 \ feet^2$

The length of the rectangle = $7\times 10^1^1$ feet

The width of the rectangle = $\rm 1.6\times 10x$ feet

After putting the values in the formula, we get:

$\rm 1.12\times10^4^5 =7\times 10^1^1\times\rm 1.6\times 10x$

$\rm x =\frac{1.12\times10^4^5}{7\times 10^1^1\times\rm 1.6\times 10}$

$\rm x =\frac{1.12\times10^4^5}{7\times 10^1^1\times\rm 1.6\times 10} \\\\\rm x = 0.1\times 10^3^3$

$\rm x =10^3^2$

Thus, the value of x is $10^3^2$

Learn more about the area here:

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