Question

60g of a compound on analysis gave 24 g C, 4 g H and 32 g O. What's the emperical formula?​

Answer 1

$\text{Given,}$

$\text{Mass of C = 24g(w) for C}$

$\text{mass of H= 4g(w) for H and mass of C= 32g(w)}$

$\text{for O( ∵n= w/m)}$

$\therefore \text{ moles of C =} \frac{24}{12 } = 2$

$\text{moles of H =} \frac{4}{1} = 4$

$\therefore \text{ moles of O=} \frac{32}{16} = 2$

$\text{Thus, Simple Ratio is= 2:4:2 also be written as 1:2:1}$

$\text{Hence, Emperical Formula=} \text{CH}_2 \text{O}$

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