So I have this question here, can someone please help me?

Answer:
Use tan trig ratio:
[tex]\sf tan(\theta)=\dfrac{O}{A}[/tex]
where [tex]\theta[/tex] is the angle, O is the side opposite the angle, and A is the side adjacent the angle
Given:
Substituting these values into the formula:
[tex]\implies \tan(39)=\dfrac{10}{x}[/tex]
Multiplying both sides by [tex]x[/tex]:
[tex]\implies x\tan(39)=10[/tex]
Dividing both sides by [tex]\tan(39)[/tex] :
[tex]\implies x=\dfrac{10}{\tan(39)}[/tex]
[tex]\implies x=12.34897157...[/tex]
[tex]\implies x=12.3 \ \textsf{(nearest tenth)}[/tex]
[tex]\\ \rm\rightarrowtail tan\theta=\dfrac{Perpendicular}{Base}[/tex]
[tex]\\ \rm\rightarrowtail tan51=\dfrac{x}{10}[/tex]
[tex]\\ \rm\rightarrowtail x=10tan51[/tex]
[tex]\\ \rm\rightarrowtail x=10(1.2348971565350)[/tex]
[tex]\\ \rm\rightarrowtail x=12.348971565350[/tex]