Answer:
Step-by-step explanation:
In exponent division, if bases are same, then subtract the powers.
[tex]\dfrac{x^{7}y^{3}}{xy^{-4}} = x^{7-1}*y^{3-(-4)}\\\\\\=x^{6}*y^{3+4}\\\\=x^{6}y^{7}[/tex]
Hello!
Recall the Properties of Exponents:
[tex]\bold{\displaystyle\frac{a^m}{a^n} =a^{m-n}}[/tex]
Let's use it to simplify:
[tex]\bold{\displaystyle\frac{x^7y^3}{xy^{-4}}}[/tex]
x = x¹
[tex]\bold{\displaystyle\frac{x^6y^3}{y^{-4}}}[/tex]
[tex]\bold{\displaystyle\frac{x^7y^3}{y^{-4}}}[/tex]
Subtract:
[tex]\bold{x^6y^{3-(-4)}}[/tex]
Which is the same as
[tex]\bold{x^6y^{3+4}}[/tex]
Final Answer:
[tex]\huge\boxed{\mathfrak{Answer:{\boxed{\star{\boxed{\bold{x^6y^7}}}}}}}[/tex]
Hope everything is clear.
Let me know if you have any questions!
#KeepLearning
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