Question

The altitude (or height) of a triangle is increasing at a rate of 2.5cm/min while the area of the triangle is increasing at a rate of 3cm2/min. At what rate (in cm/min) is the base of the triangle changing when the altitude is 12cm and the area is 84cm2?

Answer 1

Answer:

$2.90M\min_{min}$

Step-by-step explanation:

$Cellulation:\ let\ the\ fime\\ is\ x\ m\ in\ then\ for\ the\ aftitude=12cm$

$t=4.8 min$

$So\ base\ is\ 84\times2\ mm\div12\ cm=14\ cm$

$So\ the\ vate:\ 14\ cm\div4.\ Phin$

$=2.9\cm /min$

I hope this helps you

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