Question

Please Help! Locks in 1 hour! Will give Brainlest!

Answer 1

Answer:

$\huge\orange{\sin\theta=-\frac{\sqrt 2}{2}}$

Step-by-step explanation:

$\bigg(-\frac{\sqrt 2}{2},-\frac{\sqrt 2}{2}\bigg)=(x,\: y)$

$\implies x =-\frac{\sqrt 2}{2},\: y=-\frac{\sqrt 2}{2}$

Let r be the radius of the unit circle centered at origin and passing through the point (x, y).

$\implies r^2=x^2+y^2$

$\implies r^2=\bigg(-\frac{\sqrt 2}{2}\bigg)^2+\bigg(-\frac{\sqrt 2}{2}\bigg)^2$

$\implies r^2=\frac{2}{4}+\frac{2}{4}$

$\implies r^2=\frac{1}{2}+\frac{1}{2}$

$\implies r^2=1$

$\implies r=\pm \:1$

radius of a circle can not be negative.

$\implies r=1$

$\implies \sin\theta=\frac{y}{r}\:1$

$\implies \sin\theta=\frac{-\frac{\sqrt 2}{2}}{1}\:1$

$\huge\orange{\implies \sin\theta=-\frac{\sqrt 2}{2}}$