Question

A bag has 8 red marbles, 6 green marbles, 4 blue marbles, and 2 yellow marbles. We draw three marbles, one at a time, with replacement. What is the probability that none of the three draws will be red? Write your answer as a simplified fraction

Answer 1

Answer:

27/125

Step-by-step explanation:

There are 20 marbles in the bag. 8 of them are red, so 12 of them are not red. The probability of drawing a marble that isn’t red is 12/20=3/5. Because this needs to happen 3 times, the probability of getting 0 red marbles from 3 draws is 3/5*3/5*3/5=27/125.

Answer 2

Answer: 33/171

Step-by-step explanation:

We can add the marbles together to get a total of 20 marbles. There are 4 red marbles. That means 12 aren't red. The first time, the chance of getting a not red marble is 3/5. The next time, there are 19 marbles and 11 possible not reds, so it will be 11/19. The third time there are 10 possible not reds and 18 marbles so the probability is 5/9. Multiplying them all together gets you 165/855 which can be simplified to 33/171

hope this helps, though I need to check it