Question

Please help me with four and five

Answer 1

Answer:

4. $(x + y)(x + 5y)$

5. $\left(2m+3\right)\left(m-4\right)$

Step-by-step explanation:

4.

First break it into groups:

$\left(x^2+xy\right)+\left(5xy+5y^2\right)$

Then factor out x from the first parentheses and 5y from the second one:

$x(x+y)$ $+$ $5y\left(x+y\right)$

Next, factor out x + y from the equation. This gives you:

$\left(x+y\right)\left(x+5y\right)$

5.

Break it into groups like the last one:

$\left(2m^2+3m\right)+\left(-8m-12\right)$

Then, factor out m from the first parentheses and -4 from the second parentheses:

$m\left(2m+3\right)-4\left(2m+3\right)$

Lastly, factor out 2m + 3 from the equation:

$\left(2m+3\right)\left(m-4\right)$