PLEASE HELP I'M DESPERATE
Examine the following diagram, where AP is secant to the circle at points A and B, and CP is secant to the circle at points C and D. The lines intersect outside the circle at point P. What is the length of PD?

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PLEASE HELP IM DESPERATEExamine the following diagram where AP is secant to the circle at points A and B and CP is secant to the circle at points C and D The li class=

Respuesta :

Answer:

Step-by-step explanation:

The formula for 2 secants coming out of a common point is a proportion

The formula in this case, is

PA*PB = CD *  PC

Givens

PB = 10

PA = 8 + 10 = 18

PD = X

PC = X + 20

Solution

10*18     =    x * (x + 20)                    Cross Multiply

180 = x^2 + 20x                               Remove the Brackets

180 -180 =   x^2 + 20x -180             Subtract 180 from both sides.

0 =  x^2 +20x - 180                         Combine

This factors into something not in your answer choices or even close rounded.

Make sure you have the right diagram for the right question.

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