Question

The surface tension of water in air is approximately 0.00518 lbf/ft. if the atmospheric pressure is 14.7psia, what is the pressure inside a droplet 0.01" in diameter?

Answer 1

Based on the calculations, the pressure inside this droplet is equal to 2,909.35 kPa.

Given the following data:

• Surface tension = 0.00518 lbf/ft to N/m = 0.00702 N/m.

• Atmospheric pressure = 14.7psia to kPa = 101.35 kPa.

• Diameter = 0.01 mm to m = 0.00001 m.

Radius, r = $\frac{diamter}{2} =\frac{0.0001}{2}$ = 0.000005 m.

How to determine the pressure inside a droplet.

For a droplet with only one surface, its pressure is given by this formula:

$P_1-P_2=\frac{2 \tau}{r} \\\\P_1=\frac{2 \tau}{r}+P_2$

Substituting the given parameters into the formula, we have;

$P_1=\frac{2 \times 0.00702}{0.000005} + 101.35\\\\P_1=2808+ 101.35$

Inside pressure = 2,909.35 kPa.

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