The equation of the given line is y = -3x + 5 and the coordinate point (70, -205) is on the line.
How to find the equation of a straight line
The equation of a straight line in slope-intercept form is expressed as:
y = mx + b
where:
m is the slope
b is the y-intercept
Using the coordinate points (0, 5) and (1, 2), the slope of the line is calculated as:
m = 2-5/1-0
m = -3/1
m = -3
Since the line cuts the y-axis at b = 5, hence the y intercept is 5. The required equation of the line is y = -3x + 5
Check if (70, -205) is on the line
If x= 70, calculate the value of "y"
y = -3(70) + 5
y = -210 + 5
y = - 205
Since the corresponding y-value is -205, hence the coordinate point (70, -205) is on the line.
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