Question

A clock is moving relative to an observer with a velocity that approaches the speed of light. How does the passage of time measured by the moving clock compare to the passage of time measured by a stationary clock?.

Answer 1

The moving clock records the proper time in that frame (measurements in the same place) - it measures time normally

A stationary observer observes   T = T0 / (1 - v^2 / c^2)^1/2

The stationary observer sees time is running slow for the moving clock