The equation of the circle x² + y² + 4x – 8y + 11 = 0 that has radius of 3 units and center at (–2, 4).
It is a locus of a point drawn equidistant from the center. The distance from the center to the circumference is called the radius of the circle.
The equation of the circle is x² + y² + 4x – 8y + 11 = 0
Add 9 on both sides of the equation, then we have
x² + y² + 4x – 8y + 11 + 9 = 9
x² + 4x + 4 + y² – 8y + 16 = 9
(x + 2)² + (y – 4)² = 3²
The center of the equation is (–2, 4).
More about the circle link is given below.
https://brainly.com/question/11833983
