Question

There are only 3 red counters and 5 yellow counters in a bag.
Jude takes at random 3 counters from the bag.
Work out the probability that he takes exactly one red counter.

Answer 1

The probability that Jude takes exactly one red counter is the likelihood of selecting one red counter

The probability that Jude takes exactly one red counter. is 0.4395

How to determine the probability?

The given parameters are:

Red = 3

Yellow = 5

So, the probability of selecting a red counter is:

p = 3/8

The probability of taking exactly one red counter in 3 selections is calculated as:

$P(x) = ^nC_x * p^x * (1 - p)^{n - x}$

Where:

n = 3 --- number of selections

x = 1 --- the red counter selected

So, we have:

$P(1) = ^3C_1 * (3/8)^1 * (1 - 3/8)^{3 - 1}$

This gives

$P(1) = 3 * (3/8) * (5/8)^2$

Evaluate

$P(1) = 0.4395$

Hence, the probability that Jude takes exactly one red counter. is 0.4395

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