what is the graph to j

Answer:
Substitute x = -9 and x = -3 into [tex]y=5-\dfrac13x[/tex]
[tex]\implies y=5-\dfrac13(-9)=8[/tex]
[tex]\implies y=5-\dfrac13(-3)=6[/tex]
Plot a closed circle at (-9, 8) and and open circle at (-3, 6).
Connect the points with a line segment.
Substitute x = -3 and x = 8 into [tex]y=\dfrac23x[/tex]
[tex]\implies y=\dfrac23(-3)=-2[/tex]
[tex]y=\dfrac23(8)=\dfrac{16}{3}[/tex]
Plot closed circles at (-3, 2) and (8, 16/3).
Connect the points with a line segment.