The solution of the quadratic equation using the Shri dharacharya formula is 0.31 and negative of 1.81.
It is a polynomial that is equal to zero. Polynomial of variable power 2, 1, and 0 terms are there. Any equation having one term in which the power of the variable is a maximum of 2 then it is called a quadratic equation.
The quadratic expression is (4x + 3)² = 18
On solving, we have
(4x + 3)² = 18
(4x + 3) = √18
4x = - 3 ± √18
x = -3 ± √18 / 4
x = 0.31, -1.81
More about the quadratic equation link is given below.
https://brainly.com/question/2263981
