Respuesta :

Answer:

[tex]g(x)=x^3-8x^2+9x+11[/tex]

Step-by-step explanation:

[tex]f(x)=-x^3-8x^2-9x+11[/tex]

When a function is reflected across the y-axis, negative x-values become positive, and positive x-values become negative.

Therefore, substitute -x in place of x in the function f(x):

[tex]g(x)=-(-x)^3-8(-x)^2-9(-x)+11[/tex]

We know that [tex](-x)^3=-(x^3)[/tex]

[tex]\implies -(-x)^3=--(x^3)=x^3[/tex]

We know that [tex](-x)^2=x^2[/tex]

[tex]\implies -8(-x)^2=-8(x)^2=-8x^2[/tex]

Also [tex]-9(-x)=+ \ 9x[/tex]

Therefore,

[tex]g(x)=x^3-8x^2+9x+11[/tex]

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