The surface-area-to-volume ratio for the cuboidal cell that removes waste via diffusion most efficiently is 24: 8 which is of cell A.
What is the effect of higher surface-area-to-volume ratio?
When the cell size increases, the volume increases faster than the surface area, because volume is cubed whereas surface area is present in square form. When there is more volume and less surface area, diffusion takes longer and is less effective.
So we can conclude that higher surface area as compared to volume make the diffusion process very efficient.
Learn more about diffusion here: https://brainly.com/question/94094
